1. **State the problem:** We need to find the equations of lines perpendicular to given lines (Line 4, Line 5, Line 6) passing through specific points: (3, 8), (-12, 6), and (-7, -6). 2. **Recall the rule for perpendicular slopes:** If a line has slope $m$, then a line perpendicular to it has slope $m_{\perp} = -\frac{1}{m}$. 3. **Find slopes of Lines 4, 5, and 6 from Part I:** Since Part I is not provided, let's assume the slopes are known or given as follows (for demonstration): - Slope of Line 4: $m_4$ - Slope of Line 5: $m_5$ - Slope of Line 6: $m_6$ 4. **Calculate perpendicular slopes:** $$ m_{10} = -\frac{1}{m_4}, \quad m_{11} = -\frac{1}{m_5}, \quad m_{12} = -\frac{1}{m_6} $$ 5. **Write the equation of each perpendicular line in point-slope form:** $$ y - y_1 = m_{\perp}(x - x_1) $$ where $(x_1, y_1)$ is the given point. 6. **Convert to slope-intercept form $y = mx + b$ by solving for $b$:** $$ b = y_1 - m_{\perp} x_1 $$ 7. **Apply to each line:** - Line 10 through $(3,8)$: $$ y = m_{10} x + b_{10} \quad \text{where} \quad b_{10} = 8 - m_{10} \times 3 $$ - Line 11 through $(-12,6)$: $$ y = m_{11} x + b_{11} \quad \text{where} \quad b_{11} = 6 - m_{11} \times (-12) $$ - Line 12 through $(-7,-6)$: $$ y = m_{12} x + b_{12} \quad \text{where} \quad b_{12} = -6 - m_{12} \times (-7) $$ **Note:** Without the slopes of Lines 4, 5, and 6, we cannot compute exact equations. Please provide those slopes or equations from Part I to proceed with exact answers.