1. **State the problem:** Albert had 16.10 less than Peter. After Peter gave 2.50 to Albert, Peter had 4 times as much money as Albert.
2. **Define variables:** Let $P$ be the amount of money Peter had at first.
Let $A$ be the amount of money Albert had at first.
3. **Write equations from the problem:**
From the first statement:
$$A = P - 16.10$$
After Peter gives 2.50 to Albert:
Peter's money: $P - 2.50$
Albert's money: $A + 2.50$
From the second statement:
$$P - 2.50 = 4(A + 2.50)$$
4. **Substitute $A$ from the first equation into the second:**
$$P - 2.50 = 4((P - 16.10) + 2.50)$$
5. **Simplify inside the parentheses:**
$$(P - 16.10) + 2.50 = P - 13.60$$
So:
$$P - 2.50 = 4(P - 13.60)$$
6. **Expand the right side:**
$$P - 2.50 = 4P - 54.40$$
7. **Bring all terms to one side:**
$$P - 2.50 - 4P + 54.40 = 0$$
Simplify:
$$-3P + 51.90 = 0$$
8. **Isolate $P$:**
$$-3P = -51.90$$
$$P = \frac{-51.90}{-3}$$
9. **Simplify the fraction:**
$$P = \cancel{\frac{-51.90}{-3}} = 17.30$$
10. **Final answer:**
Peter had 17.30 at first.
Peter Albert Money 85B704
Step-by-step solutions with LaTeX - clean, fast, and student-friendly.