1. **State the problem:** A photograph measures 7 \(\frac{1}{2}\) cm (which is 7.5 cm) by 5 cm. It is enlarged so that the longer side becomes 24 cm. We need to find the length of the shorter side after enlargement.
2. **Identify the formula:** The enlargement keeps the aspect ratio the same, so the ratio of the sides remains constant. This means:
$$\frac{\text{original longer side}}{\text{original shorter side}} = \frac{\text{new longer side}}{\text{new shorter side}}$$
3. **Apply the known values:**
Original longer side = 7.5 cm
Original shorter side = 5 cm
New longer side = 24 cm
New shorter side = $x$ cm (unknown)
4. **Set up the proportion:**
$$\frac{7.5}{5} = \frac{24}{x}$$
5. **Solve for $x$:**
Multiply both sides by $x$:
$$7.5 \times x = 5 \times 24$$
$$7.5x = 120$$
Divide both sides by 7.5:
$$x = \frac{120}{7.5}$$
$$x = 16$$
6. **Interpretation:** The length of the shorter side after enlargement is 16 cm.
**Final answer:** 16 cm
Photo Enlargement
Step-by-step solutions with LaTeX - clean, fast, and student-friendly.