1. **State the problem:** We have a piecewise function defined as:
$$
g(x) = \begin{cases}
-2 & \text{if } -2 \leq x < -1 \\
-1 & \text{if } -1 \leq x < 0 \\
0 & \text{if } 0 \leq x < 1 \\
1 & \text{if } 1 \leq x < 2
\end{cases}
$$
We need to find the values of $g(-1)$, $g(0.25)$, and $g(1)$.
2. **Recall how to evaluate piecewise functions:** To find $g(a)$, determine which interval $a$ belongs to and use the corresponding function value.
3. **Evaluate $g(-1)$:**
Since $-1$ satisfies $-1 \leq x < 0$, we use $g(x) = -1$.
$$g(-1) = -1$$
4. **Evaluate $g(0.25)$:**
Since $0.25$ satisfies $0 \leq x < 1$, we use $g(x) = 0$.
$$g(0.25) = 0$$
5. **Evaluate $g(1)$:**
Since $1$ satisfies $1 \leq x < 2$, we use $g(x) = 1$.
$$g(1) = 1$$
**Final answers:**
$$g(-1) = -1, \quad g(0.25) = 0, \quad g(1) = 1$$
Piecewise Evaluation 0B5371
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