1. The problem asks to calculate $f(-1)$, $f(0)$, and $f(2)$ for the piecewise function: $$f(x) = \begin{cases} 8x - 4 & x < 0 \\ 8x - 8 & x \geq 0 \end{cases}$$ 2. To find $f(-1)$, since $-1 < 0$, use the first piece: $$f(-1) = 8(-1) - 4 = -8 - 4 = -12$$ 3. To find $f(0)$, since $0 \geq 0$, use the second piece: $$f(0) = 8(0) - 8 = 0 - 8 = -8$$ 4. To find $f(2)$, since $2 \geq 0$, use the second piece: $$f(2) = 8(2) - 8 = 16 - 8 = 8$$ Final answers: $$f(-1) = -12, \quad f(0) = -8, \quad f(2) = 8$$