1. **Problem statement:** We need to find how far the plane flew west, given an equation involving $c = \sqrt{2311625}$. 2. **Step 1: Calculate $c$** We start by finding the value of $c$: $$c = \sqrt{2311625}$$ 3. **Step 2: Simplify the square root** Calculate the square root: $$c \approx 1585.77$$ 4. **Step 3: Understanding the problem context** Assuming $c$ represents the hypotenuse of a right triangle where the plane's westward distance is one leg, we use the Pythagorean theorem: $$c^2 = a^2 + b^2$$ where $a$ and $b$ are the legs of the triangle. 5. **Step 4: Given values** From the problem, $a^2 = 705600$ and $b^2 = 180900$. 6. **Step 5: Verify the sum** $$705600 + 180900 = 886500$$ 7. **Step 6: Correct the equation** Since $c^2 = 2311625$, the sum of $a^2$ and $b^2$ should equal $2311625$, but it equals $886500$. So, Jocelyn's equation is incorrect. 8. **Step 7: Solve for the westward distance** Let the westward distance be $x$, and the other leg be $y$ such that: $$x^2 + y^2 = 2311625$$ If $y^2 = 180900$, then: $$x^2 = 2311625 - 180900 = 2130725$$ 9. **Step 8: Calculate $x$** $$x = \sqrt{2130725} \approx 1460.8$$ 10. **Final answer:** The plane flew approximately **1460.8** units west, rounded to the nearest tenth.