1. **State the problem:** Find the point of intersection (POI) of the two lines given by the equations: $$6x + 2y = -6$$ $$x + 5y = -15$$ 2. **Method:** We will solve this system of linear equations using substitution or elimination. Here, substitution is straightforward. 3. **Isolate $x$ in the second equation:** $$x + 5y = -15 \implies x = -15 - 5y$$ 4. **Substitute $x$ into the first equation:** $$6(-15 - 5y) + 2y = -6$$ 5. **Simplify:** $$-90 - 30y + 2y = -6$$ $$-90 - 28y = -6$$ 6. **Isolate $y$:** $$-28y = -6 + 90$$ $$-28y = 84$$ 7. **Divide both sides by $-28$:** $$y = \frac{84}{\cancel{-28}} \cancel{-1} = -3$$ 8. **Substitute $y = -3$ back into $x = -15 - 5y$:** $$x = -15 - 5(-3) = -15 + 15 = 0$$ 9. **Final answer:** The point of intersection is $$\boxed{(0, -3)}$$