Subjects algebra

Point Line Check E37F47

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1. **State the problem:** We are given a point $P = (7, 27.5)$ and a linear function $y = 2x + 45$. We want to verify the value of $y$ at $x=7$ and understand the graph description. 2. **Evaluate the function at $x=7$:** Substitute $x=7$ into the function: $$y = 2(7) + 45$$ 3. **Calculate:** $$y = 14 + 45 = 59$$ 4. **Compare with the point $P$:** The point $P$ has coordinates $(7, 27.5)$, but the function value at $x=7$ is $59$. This means $P$ does not lie on the line $y=2x+45$. 5. **Interpret the graph description:** The graph described is a downward linear graph starting at about 45 dollars when $x=0$ and going down to 0 dollars at about $x=19$. This suggests a different linear function, likely with a negative slope. 6. **Find the equation of the line from the graph description:** - At $x=0$, $y=45$ - At $x=19$, $y=0$ Slope $m = \frac{0 - 45}{19 - 0} = \frac{-45}{19}$ Equation: $$y = mx + b = -\frac{45}{19}x + 45$$ 7. **Check if point $P$ lies on this line:** $$y = -\frac{45}{19}(7) + 45 = -\frac{315}{19} + 45 = 45 - 16.58 = 28.42$$ The $y$-value is approximately $28.42$, close to $27.5$, so $P$ is near this line. **Final answer:** The point $P=(7,27.5)$ does not lie on $y=2x+45$ but is close to the line $y = -\frac{45}{19}x + 45$ which matches the graph description.