1. The problem is to understand the point $(-2,-\sqrt{2})$ in the coordinate plane. 2. This point has an $x$-coordinate of $-2$ and a $y$-coordinate of $-\sqrt{2}$. 3. The $x$-coordinate tells us the horizontal position: $-2$ means 2 units to the left of the origin. 4. The $y$-coordinate tells us the vertical position: $-\sqrt{2}$ means approximately $-1.414$, so about 1.414 units below the origin. 5. Together, the point $(-2,-\sqrt{2})$ is located in the third quadrant of the Cartesian plane, where both $x$ and $y$ are negative. 6. No further calculations are needed unless asked for distance from origin or other properties.