Subjects algebra

Point Slope Line

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1. **State the problem:** Find the equation of the line in point-slope form passing through points $(-6, 38)$ and $(2, -22)$. 2. **Formula:** The point-slope form of a line is given by $$y - y_1 = m(x - x_1)$$ where $m$ is the slope and $(x_1, y_1)$ is a point on the line. 3. **Calculate the slope $m$:** $$m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{-22 - 38}{2 - (-6)} = \frac{-60}{8} = -\frac{15}{2}$$ 4. **Choose a point to plug in:** Use $(-6, 38)$. 5. **Write the equation:** Substitute $m = -\frac{15}{2}$, $x_1 = -6$, and $y_1 = 38$ into the point-slope form: $$y - 38 = -\frac{15}{2}(x - (-6)) = -\frac{15}{2}(x + 6)$$ 6. **Interpretation:** This matches option D. **Final answer:** $$\boxed{y - 38 = -\frac{15}{2}(x + 6)}$$