1. **State the problem:** We need to check if the point $(-5, 2)$ satisfies the system of equations: $$x = -5$$ $$y = 2x + 10$$ 2. **Check the first equation:** Substitute $x = -5$ into the first equation: $$x = -5$$ Since the point's $x$-coordinate is $-5$, it satisfies the first equation. 3. **Check the second equation:** Substitute $x = -5$ into the second equation to find $y$: $$y = 2(-5) + 10$$ $$y = -10 + 10$$ $$y = 0$$ 4. **Compare with the point's $y$-coordinate:** The point has $y = 2$, but the equation gives $y = 0$ when $x = -5$. 5. **Conclusion:** Since $y = 2$ does not equal $0$, the point $(-5, 2)$ does not satisfy the second equation and therefore is not a solution to the system. **Final answer:** No, $(-5, 2)$ is not a solution to the system of equations.