1. The problem asks to find the coordinates of point Z on the graph of the linear equation $$y = 0.8x - 3$$ when $$x = 2$$. 2. The formula for a linear function is $$y = mx + b$$, where $$m$$ is the slope and $$b$$ is the y-intercept. 3. To find the y-coordinate of point Z, substitute $$x = 2$$ into the equation: $$y = 0.8(2) - 3$$ 4. Calculate the multiplication: $$y = 1.6 - 3$$ 5. Simplify the subtraction: $$y = -1.4$$ 6. Therefore, the coordinates of point Z are $$(2, -1.4)$$. This means when $$x = 2$$, the point on the line is at $$y = -1.4$$.