1. **State the problem:** We need to determine which ordered pairs $(x,y)$ satisfy the equation $$5x = 7y + 15$$. 2. **Rewrite the equation:** The equation relates $x$ and $y$ as $$5x = 7y + 15$$. 3. **Check each ordered pair:** Substitute each pair into the equation and verify if the equality holds. - For $(5, -3)$: $$5(5) = 25$$ and $$7(-3) + 15 = -21 + 15 = -6$$ so $$25 \neq -6$$ (No) - For $(0, 7)$: $$5(0) = 0$$ and $$7(7) + 15 = 49 + 15 = 64$$ so $$0 \neq 64$$ (No) - For $(-7, 5)$: $$5(-7) = -35$$ and $$7(5) + 15 = 35 + 15 = 50$$ so $$-35 \neq 50$$ (No) - For $(-3, 3)$: $$5(-3) = -15$$ and $$7(3) + 15 = 21 + 15 = 36$$ so $$-15 \neq 36$$ (No) - For $(3, 0)$: $$5(3) = 15$$ and $$7(0) + 15 = 0 + 15 = 15$$ so $$15 = 15$$ (Yes) - For $(3, 7)$: $$5(3) = 15$$ and $$7(7) + 15 = 49 + 15 = 64$$ so $$15 \neq 64$$ (No) 4. **Conclusion:** Only the ordered pair $(3, 0)$ satisfies the equation.