1. **State the problem:** We need to factor the polynomial $$36x^2y^4 + 12x^3y^2 + 12x^4y^3$$ and match it with the given factors $$-4xy$$ and $$12x^2y^2$$.
2. **Identify the greatest common factor (GCF):** Look for the common factors in each term.
- Coefficients: GCF of 36, 12, and 12 is 12.
- Variables: For $$x^2, x^3, x^4$$ the minimum power is $$x^2$$.
- For $$y^4, y^2, y^3$$ the minimum power is $$y^2$$.
So, the GCF is $$12x^2y^2$$.
3. **Factor out the GCF:**
$$
36x^2y^4 + 12x^3y^2 + 12x^4y^3 = 12x^2y^2(\frac{36x^2y^4}{12x^2y^2} + \frac{12x^3y^2}{12x^2y^2} + \frac{12x^4y^3}{12x^2y^2})
$$
4. **Simplify inside the parentheses:**
$$
= 12x^2y^2(3y^2 + x + x^2y)
$$
5. **Check if the polynomial inside parentheses can be factored further:**
- The terms are $$3y^2$$, $$x$$, and $$x^2y$$.
- No common factors or simple factorization applies here.
6. **Match with given factors:**
- The factor $$12x^2y^2$$ matches the GCF factored out.
- The other factor is the remaining polynomial $$3y^2 + x + x^2y$$.
7. **Regarding $$-4xy$$:**
- It is not a factor of the given polynomial since it does not divide all terms evenly.
**Final answer:**
$$36x^2y^4 + 12x^3y^2 + 12x^4y^3 = 12x^2y^2(3y^2 + x + x^2y)$$
**Summary:**
- Polynomial: $$36x^2y^4 + 12x^3y^2 + 12x^4y^3$$
- Factor: $$12x^2y^2$$
- Remaining factor: $$3y^2 + x + x^2y$$
- $$-4xy$$ is not a factor of the polynomial.
Polynomial Factoring 566Cc4
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