1. **State the problem:**
We are given the expression $96x^3 - 12x^2 - 112x + 14$ and a sequence of factorizations:
$$2(48x^2 - 6x^2)(-56x + 7)$$
$$6x^2(8x - 1) - 7(8x + 1)$$
$$2(8x - 1)(6x^2 - 7)$$
We want to verify the factorization and understand the steps.
2. **Start with the original expression:**
$$96x^3 - 12x^2 - 112x + 14$$
3. **Group terms to factor by grouping:**
Group as $(96x^3 - 12x^2) + (-112x + 14)$.
4. **Factor out common factors in each group:**
From the first group: $12x^2$ is common, so
$$12x^2(8x - 1)$$
From the second group: $-14$ is common, so
$$-14(8x - 1)$$
5. **Rewrite the expression:**
$$12x^2(8x - 1) - 14(8x - 1)$$
6. **Factor out the common binomial factor $(8x - 1)$:**
$$ (8x - 1)(12x^2 - 14) $$
7. **Simplify the second factor:**
Factor out 2:
$$ (8x - 1)(2(6x^2 - 7)) = 2(8x - 1)(6x^2 - 7) $$
8. **Final factorization:**
$$ 2(8x - 1)(6x^2 - 7) $$
**Explanation:**
We used factoring by grouping, which involves grouping terms to find common factors, then factoring out the common binomial. We also factored out constants to simplify the expression.
**Answer:**
$$\boxed{2(8x - 1)(6x^2 - 7)}$$
Polynomial Factorization 769E16
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