1. **State the problem:** The population doubles every 28 months. The current population is 50,000. We want to find the population 4 years from now. 2. **Identify the formula:** Since the population doubles every 28 months, this is an exponential growth problem. The formula for exponential growth is: $$ P(t) = P_0 \times 2^{\frac{t}{T}} $$ where: - $P(t)$ is the population at time $t$, - $P_0$ is the initial population, - $T$ is the doubling period (28 months), - $t$ is the time elapsed. 3. **Convert 4 years to months:** $$ 4 \text{ years} = 4 \times 12 = 48 \text{ months} $$ 4. **Calculate the population after 48 months:** $$ P(48) = 50,000 \times 2^{\frac{48}{28}} $$ Simplify the exponent: $$ \frac{48}{28} = \frac{12}{7} \approx 1.714 $$ So: $$ P(48) = 50,000 \times 2^{1.714} $$ 5. **Calculate $2^{1.714}$:** $$ 2^{1.714} \approx 3.29 $$ 6. **Find the final population:** $$ P(48) = 50,000 \times 3.29 = 164,500 $$ **Answer:** The population 4 years from now will be approximately 164,500.