1. The problem asks to find the value of $2^3 \times 2^0$. 2. Recall the rule for multiplying powers with the same base: $a^m \times a^n = a^{m+n}$. 3. Applying this rule, we get: $$2^3 \times 2^0 = 2^{3+0} = 2^3$$ 4. Now evaluate $2^3$: $$2^3 = 2 \times 2 \times 2 = 8$$ 5. Therefore, the value of $2^3 \times 2^0$ is 8. 6. Your answer of 8 is correct!