1. The problem asks us to find the value of the fraction $$\frac{59049}{729}$$ using the given table of powers of 9. 2. From the table, we see that $$59049 = 9^5$$ and $$729 = 9^3$$. 3. Substitute these values into the fraction: $$\frac{59049}{729} = \frac{9^5}{9^3}$$ 4. Use the law of exponents for division: $$\frac{a^m}{a^n} = a^{m-n}$$. 5. Therefore, $$\frac{9^5}{9^3} = 9^{5-3} = 9^2$$ 6. From the table, $$9^2 = 81$$. 7. So, the value of the fraction $$\frac{59049}{729}$$ is $$81$$. Final answer: $$81$$