Subjects algebra

Power Plant Calculation 1Fa4D8

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1. **Evaluate** $5.01 \times 10^3 = 4.11 \times 10^3$. This is a comparison, not an operation, so the values are: $5.01 \times 10^3 = 5010$ $4.11 \times 10^3 = 4110$ 2. **Evaluate and add** $0.0899 + 3.31 \times 10^{-3}$ and express the answer in scientific notation. 3. **Calculate the total power** a power plant must produce per day to serve both cities. Given: City A uses $2.5 \times 10^9$ watts per day City B uses $7.3 \times 10^8$ watts per day **Step 1:** Add the power usage of both cities: $$2.5 \times 10^9 + 7.3 \times 10^8$$ Rewrite $7.3 \times 10^8$ as $0.73 \times 10^9$ to have the same power of ten: $$2.5 \times 10^9 + 0.73 \times 10^9 = (2.5 + 0.73) \times 10^9 = 3.23 \times 10^9$$ **Step 2:** The power plant must produce $3.23 \times 10^9$ watts per day. **Final answers:** - $0.0899 + 3.31 \times 10^{-3} = 0.0899 + 0.00331 = 0.09321$ Express in scientific notation: $$0.09321 = 9.321 \times 10^{-2}$$ - Power plant output needed: $3.23 \times 10^9$ watts per day.