1. The problem asks to find the value of $5y^0$ where $y > 0$. 2. Recall the rule: any nonzero number raised to the power of 0 is 1, i.e., $a^0 = 1$ for $a \neq 0$. 3. Since $y > 0$, $y^0 = 1$. 4. Substitute this back into the expression: $5y^0 = 5 \times 1 = 5$. 5. Therefore, the value of $5y^0$ is 5 because $y^0$ equals 1 for any positive $y$.