1. **State the problem:** We need to express the numbers 60, 88, and 120 as products of their prime factors. 2. **Recall the prime factorization method:** Prime factorization means breaking down a number into the product of prime numbers only. 3. **Factorize 60:** - Start dividing by the smallest prime 2: $60 \div 2 = 30$ - Divide 30 by 2 again: $30 \div 2 = 15$ - 15 is not divisible by 2, try next prime 3: $15 \div 3 = 5$ - 5 is a prime number. - So, $60 = 2 \times 2 \times 3 \times 5 = 2^2 \times 3 \times 5$ 4. **Factorize 88:** - Divide by 2: $88 \div 2 = 44$ - Divide 44 by 2: $44 \div 2 = 22$ - Divide 22 by 2: $22 \div 2 = 11$ - 11 is prime. - So, $88 = 2 \times 2 \times 2 \times 11 = 2^3 \times 11$ 5. **Factorize 120:** - Divide by 2: $120 \div 2 = 60$ - Divide 60 by 2: $60 \div 2 = 30$ - Divide 30 by 2: $30 \div 2 = 15$ - Divide 15 by 3: $15 \div 3 = 5$ - 5 is prime. - So, $120 = 2 \times 2 \times 2 \times 3 \times 5 = 2^3 \times 3 \times 5$ **Final answers:** - $60 = 2^2 \times 3 \times 5$ - $88 = 2^3 \times 11$ - $120 = 2^3 \times 3 \times 5$