1. **Problem Statement:**
You asked why the term $50t$ was added when simplifying the profit equation in problem b.
2. **Recall the profit equation:**
Profit $P$ is revenue minus cost:
$$P = R - C$$
Given:
$$R = -50(t - 3)^2 + 450$$
$$C = 600 - 50t$$
3. **Substitute $R$ and $C$ into $P$:**
$$P = [-50(t - 3)^2 + 450] - [600 - 50t]$$
4. **Distribute the minus sign over the cost:**
$$P = -50(t - 3)^2 + 450 - 600 + 50t$$
5. **Explanation:**
When subtracting the entire cost expression, the minus sign applies to both terms inside the brackets:
- The $600$ becomes $-600$
- The $-50t$ becomes $+50t$ because $-(-50t) = +50t$
6. **Simplify constants:**
$$450 - 600 = -150$$
7. **Final simplified profit equation:**
$$P = -50(t - 3)^2 + 50t - 150$$
**Summary:** The $50t$ term appears because subtracting $-50t$ is equivalent to adding $50t$. This is a standard rule of algebra when subtracting expressions inside parentheses.
Profit Equation Explanation B833Cf
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