Subjects algebra

Pumpkin Cost 9404Bb

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1. **State the problem:** A customer bought a pumpkin weighing 4.8 kilograms (rounded to the nearest tenth) and paid 1.38 per pound. We need to find which total amount paid is possible from the given options. 2. **Convert kilograms to pounds:** Since 1 kilogram = 2.20462 pounds, the pumpkin's weight in pounds is approximately: $$4.8 \times 2.20462 = 10.582176 \text{ pounds}$$ 3. **Consider rounding of weight:** The mass 4.8 kg is rounded to the nearest tenth, so the actual mass could be between 4.75 kg and 4.85 kg. Convert these to pounds: $$4.75 \times 2.20462 = 10.472945$$ $$4.85 \times 2.20462 = 10.692377$$ 4. **Calculate possible total cost range:** Multiply the weight range by the price per pound: $$10.472945 \times 1.38 = 14.451462$$ $$10.692377 \times 1.38 = 14.757479$$ So, the total cost is between approximately $14.45 and $14.76. 5. **Compare with given options:** - A: 6.62 (too low) - B: 9.66 (too low) - C: 13.32 (too low) - D: 14.46 (within the range) **Answer:** D 14.46