1. **State the problem:** Drew places 11 less than 3 times the number of pieces Larry places. Drew places at least 10 pieces. We need to find how many pieces Larry places. 2. **Define variables:** Let $L$ be the number of pieces Larry places. 3. **Write the expression for Drew's pieces:** Drew places $3L - 11$ pieces. 4. **Set up the inequality:** Since Drew places at least 10 pieces, we have: $$3L - 11 \geq 10$$ 5. **Solve the inequality:** $$3L - 11 \geq 10$$ $$3L \geq 10 + 11$$ $$3L \geq 21$$ 6. **Divide both sides by 3:** $$\cancel{3}L \geq \frac{21}{\cancel{3}}$$ $$L \geq 7$$ 7. **Interpretation:** Larry must place at least 7 pieces. **Final answer:** Larry places at least 7 pieces.