1. **State the problem:** Solve the quadratic equation $$4x^2 - 5 = 4(x - 5)$$.
2. **Rewrite the equation:** Expand the right side:
$$4x^2 - 5 = 4x - 20$$
3. **Bring all terms to one side:**
$$4x^2 - 5 - 4x + 20 = 0$$
Simplify:
$$4x^2 - 4x + 15 = 0$$
4. **Identify coefficients:**
Here, $$a = 4$$, $$b = -4$$, and $$c = 15$$.
5. **Use the quadratic formula:**
$$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$$
6. **Calculate the discriminant:**
$$\Delta = b^2 - 4ac = (-4)^2 - 4 \times 4 \times 15 = 16 - 240 = -224$$
7. **Interpret the discriminant:**
Since $$\Delta < 0$$, there are no real solutions; the solutions are complex.
8. **Find the complex solutions:**
$$x = \frac{-(-4) \pm \sqrt{-224}}{2 \times 4} = \frac{4 \pm \sqrt{-224}}{8}$$
9. **Simplify the square root:**
$$\sqrt{-224} = \sqrt{-1 \times 224} = i \sqrt{224}$$
Factor 224:
$$224 = 16 \times 14$$
So,
$$\sqrt{224} = \sqrt{16 \times 14} = 4 \sqrt{14}$$
10. **Write the final solutions:**
$$x = \frac{4 \pm 4i \sqrt{14}}{8} = \frac{4}{8} \pm \frac{4i \sqrt{14}}{8} = \frac{1}{2} \pm \frac{i \sqrt{14}}{2}$$
**Final answer:**
$$x = \frac{1}{2} \pm \frac{i \sqrt{14}}{2}$$
Quadratic Complex 93215D
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