1. **Problem Statement:** Find the value of the function $y = 2x^2 - 3x + 1$ when $x = 4$. 2. **Formula and Rules:** The function is a quadratic polynomial given by: $$y = 2x^2 - 3x + 1$$ To find $y$ for a specific $x$, substitute the value of $x$ into the equation and simplify. 3. **Substitution:** Substitute $x = 4$: $$y = 2(4)^2 - 3(4) + 1$$ 4. **Simplification:** Calculate powers and products: $$y = 2 \times 16 - 12 + 1$$ $$y = 32 - 12 + 1$$ 5. **Final Calculation:** $$y = 20 + 1 = 21$$ **Answer:** When $x = 4$, $y = 21$.