1. **State the problem:** We need to match each quadratic expression with its correct factored form.
2. **Recall the difference of squares formula:**
$$a^2 - b^2 = (a - b)(a + b)$$
This formula helps factor expressions that are the difference of two perfect squares.
3. **Analyze each quadratic expression:**
- Expression 1: $45y^{2} - 80x^{2}$
- Factor out the greatest common factor (GCF):
$$45y^{2} - 80x^{2} = 5(9y^{2} - 16x^{2})$$
- Recognize $9y^{2} = (3y)^2$ and $16x^{2} = (4x)^2$, so:
$$5(9y^{2} - 16x^{2}) = 5((3y)^2 - (4x)^2) = 5(3y - 4x)(3y + 4x)$$
- Expression 2: $160x^{2} - 90y^{2}$
- Factor out GCF:
$$160x^{2} - 90y^{2} = 10(16x^{2} - 9y^{2})$$
- Recognize $16x^{2} = (4x)^2$ and $9y^{2} = (3y)^2$, so:
$$10((4x)^2 - (3y)^2) = 10(4x - 3y)(4x + 3y)$$
- Expression 3: $80y^{2} - 45x^{2}$
- Factor out GCF:
$$80y^{2} - 45x^{2} = 5(16y^{2} - 9x^{2})$$
- Recognize $16y^{2} = (4y)^2$ and $9x^{2} = (3x)^2$, so:
$$5((4y)^2 - (3x)^2) = 5(4y - 3x)(4y + 3x)$$
- Expression 4: $64x^{2} - 36y^{2}$
- Factor out GCF:
$$64x^{2} - 36y^{2} = 4(16x^{2} - 9y^{2})$$
- Recognize $16x^{2} = (4x)^2$ and $9y^{2} = (3y)^2$, so:
$$4((4x)^2 - (3y)^2) = 4(4x - 3y)(4x + 3y)$$
4. **Match each expression with its factored form:**
- $45y^{2} - 80x^{2} = 5(3y - 4x)(3y + 4x)$
- $160x^{2} - 90y^{2} = 10(4x - 3y)(4x + 3y)$
- $80y^{2} - 45x^{2} = 5(4y - 3x)(4y + 3x)$
- $64x^{2} - 36y^{2} = 4(4x - 3y)(4x + 3y)$
This completes the matching of quadratic expressions to their factored forms using the difference of squares formula.
Quadratic Factoring 72Ebeb
Step-by-step solutions with LaTeX - clean, fast, and student-friendly.