1. Stating the problem: Solve the equation $$4r^2 - 10 = -26$$ for $$r$$. 2. Add 10 to both sides to isolate the quadratic term: $$4r^2 - 10 + 10 = -26 + 10$$ $$4r^2 = -16$$ 3. Divide both sides by 4 to solve for $$r^2$$: $$r^2 = \frac{-16}{4} = -4$$ 4. Since $$r^2 = -4$$, take the square root of both sides: $$r = \pm \sqrt{-4}$$ 5. Recall that $$\sqrt{-1} = i$$, the imaginary unit, so: $$r = \pm 2i$$ 6. Therefore, the solutions are $$r = \pm 2i$$. 7. Comparing with the options: A) $$\pm 2i$$ B) $$\pm i\sqrt{2}$$ C) 2 D) -4 The correct answer is A) $$\pm 2i$$.