Subjects algebra

Quadratic Polynomial 06314D

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1. **Problem:** Create a quadratic polynomial whose sum and product of zeros are $\frac{1}{4}$ and $-1$ respectively. 2. **Formula:** For a quadratic polynomial $ax^2 + bx + c = 0$, the sum of zeros $\alpha + \beta = -\frac{b}{a}$ and the product of zeros $\alpha \beta = \frac{c}{a}$. 3. **Step:** Given sum of zeros $= \frac{1}{4}$ and product of zeros $= -1$, assume $a=1$ for simplicity. 4. **Construct polynomial:** Using the relations, the polynomial is $$x^2 - \left(\frac{1}{4}\right)x - 1 = 0$$ 5. **Explanation:** We use the sum and product of zeros to form the polynomial as $x^2 - (\text{sum})x + (\text{product}) = 0$. **Final answer:** $$x^2 - \frac{1}{4}x - 1 = 0$$