1. The problem is not explicitly stated, but since the user requested "calculation only," I will provide a sample algebraic calculation. 2. Consider solving the quadratic equation $$x^2 - 5x + 6 = 0$$. 3. Use the quadratic formula: $$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$$ where $a=1$, $b=-5$, and $c=6$. 4. Calculate the discriminant: $$\Delta = b^2 - 4ac = (-5)^2 - 4 \times 1 \times 6 = 25 - 24 = 1$$. 5. Find the roots: $$x = \frac{-(-5) \pm \sqrt{1}}{2 \times 1} = \frac{5 \pm 1}{2}$$. 6. Calculate each root: $$x_1 = \frac{5 + 1}{2} = \frac{6}{2} = 3$$ $$x_2 = \frac{5 - 1}{2} = \frac{4}{2} = 2$$ 7. Final answer: The solutions to the equation are $x=3$ and $x=2$.