1. **State the problem:** Solve the equation $$4x^2 + 7 = 71$$ for $$x$$.
2. **Isolate the term with $$x$$:** Subtract 7 from both sides:
$$4x^2 + 7 - 7 = 71 - 7$$
$$4x^2 = 64$$
3. **Divide both sides by 4 to solve for $$x^2$$:**
$$\frac{4x^2}{\cancel{4}} = \frac{64}{\cancel{4}}$$
$$x^2 = 16$$
4. **Take the square root of both sides:**
$$x = \pm \sqrt{16}$$
5. **Simplify the square root:**
$$x = \pm 4$$
**Final answer:** $$x = \pm 4$$
Quadratic Solution 391616
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