1. **State the problem:** Solve the quadratic equation $x^2 - 5x + 6 = 0$. 2. **Formula and rules:** The quadratic equation is generally $ax^2 + bx + c = 0$. We can solve it by factoring, completing the square, or using the quadratic formula: $$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$$ 3. **Identify coefficients:** Here, $a=1$, $b=-5$, and $c=6$. 4. **Calculate the discriminant:** $$\Delta = b^2 - 4ac = (-5)^2 - 4 \times 1 \times 6 = 25 - 24 = 1$$ 5. **Since $\Delta > 0$, there are two real roots. Use the quadratic formula:** $$x = \frac{-(-5) \pm \sqrt{1}}{2 \times 1} = \frac{5 \pm 1}{2}$$ 6. **Calculate each root:** - $x_1 = \frac{5 + 1}{2} = \frac{6}{2} = 3$ - $x_2 = \frac{5 - 1}{2} = \frac{4}{2} = 2$ 7. **Answer:** The solutions to the equation are $x=3$ and $x=2$.