1. **State the problem:** Solve the quadratic equation $$12x^2 - 48 = 0$$.
2. **Formula and rules:** To solve quadratic equations of the form $$ax^2 + bx + c = 0$$, we can isolate $$x^2$$ and then take the square root of both sides.
3. **Step 1: Isolate the quadratic term.**
$$12x^2 - 48 = 0$$
Add 48 to both sides:
$$12x^2 = 48$$
4. **Step 2: Divide both sides by 12 to solve for $$x^2$$.**
$$\cancel{12}x^2 = \cancel{12}4$$
$$x^2 = 4$$
5. **Step 3: Take the square root of both sides.**
$$x = \pm \sqrt{4}$$
$$x = \pm 2$$
6. **Final answer:**
The solutions to the equation are $$x = 2$$ and $$x = -2$$.
Quadratic Solve Bbf06B
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