1. **State the problem:** Solve the equation $x^2 - t = 0$ for $t$ given specific values of $x$. 2. **Formula and explanation:** The equation can be rearranged to find $t$ as $t = x^2$. This means $t$ is the square of $x$. 3. **Calculate for $x=4$:** $$t = 4^2 = 16$$ 4. **Calculate for $x=-4$:** $$t = (-4)^2 = 16$$ 5. **Interpretation:** Both $x=4$ and $x=-4$ give the same value $t=16$. This is because squaring a negative number results in a positive number. 6. **Graph shape:** The graph of $y = x^2 - t$ is a parabola opening upwards. The solutions $x = \\pm 4$ correspond to the points where the parabola intersects the line $y=0$ when $t=16$. **Final answer:** $t = 16$ for both $x=4$ and $x=-4$.