1. The problem is to solve the quadratic equation $x^2 - 7x + 12 = 0$ by graphing the related function and finding its zeros. 2. The related function is $y = x^2 - 7x + 12$. 3. To find the zeros, we look for the values of $x$ where $y=0$. 4. We can factor the quadratic: $$x^2 - 7x + 12 = (x - 3)(x - 4)$$ 5. Setting each factor equal to zero gives: $$x - 3 = 0 \Rightarrow x = 3$$ $$x - 4 = 0 \Rightarrow x = 4$$ 6. These are the zeros of the function, meaning the points where the graph crosses the x-axis. 7. Graphing $y = x^2 - 7x + 12$ will show the parabola intersecting the x-axis at $x=3$ and $x=4$. 8. Therefore, the solutions to the equation $x^2 - 7x + 12 = 0$ are $x = 3$ and $x = 4$.