1. **State the problem:** Find the zeros of the function $$g(x) = 4x^2 - 484$$. The zeros are the values of $$x$$ where $$g(x) = 0$$. 2. **Set the function equal to zero:** $$4x^2 - 484 = 0$$ 3. **Add 484 to both sides:** $$4x^2 = 484$$ 4. **Divide both sides by 4:** $$\cancel{4}x^2 = \cancel{4}121$$ $$x^2 = 121$$ 5. **Take the square root of both sides:** $$x = \pm \sqrt{121}$$ 6. **Simplify the square root:** $$x = \pm 11$$ 7. **Write the solutions from least to greatest:** $$x = -11, 11$$ **Final answer:** Lesser $$x = -11$$ Greater $$x = 11$$