Subjects algebra

Rate Change Temperature F02479

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1. **Problem 9 is not provided in the user's message, so it cannot be answered.** 2. **Problem 10: Find the rate of change in temperature from 6:00 a.m. to 2:00 p.m.** 3. The formula for rate of change (slope) is: $$m = \frac{y_2 - y_1}{x_2 - x_1}$$ where $y$ represents temperature and $x$ represents time in hours. 4. Assign values: - $x_1 = 6$ (6:00 a.m.) - $y_1 = 58$ (temperature at 6:00 a.m.) - $x_2 = 14$ (2:00 p.m. is 14:00 in 24-hour time) - $y_2 = 76$ (temperature at 2:00 p.m.) 5. Calculate the rate of change: $$m = \frac{76 - 58}{14 - 6} = \frac{18}{8}$$ 6. Simplify the fraction: $$m = \frac{\cancel{18}^{9}}{\cancel{8}^{4}} = \frac{9}{4}$$ 7. **Answer:** The temperature increases at a rate of $\frac{9}{4}$ degrees per hour, or 2.25 degrees per hour.