1. **Problem:** Given that $(4a + 2b) : a = 19 : 4$ and $b : c = 7 : 3$, find the ratio $a : b : c$.
2. **Step 1: Express the first ratio as an equation.**
$\frac{4a + 2b}{a} = \frac{19}{4}$
3. **Step 2: Simplify the left side.**
$\frac{4a + 2b}{a} = \frac{4a}{a} + \frac{2b}{a} = 4 + 2\frac{b}{a}$
4. **Step 3: Set up the equation and solve for $\frac{b}{a}$.**
$$4 + 2\frac{b}{a} = \frac{19}{4}$$
$$2\frac{b}{a} = \frac{19}{4} - 4 = \frac{19}{4} - \frac{16}{4} = \frac{3}{4}$$
$$\frac{b}{a} = \frac{3}{8}$$
5. **Step 4: Express $b$ in terms of $a$.**
$$b = \frac{3}{8}a$$
6. **Step 5: Use the second ratio $b : c = 7 : 3$ to express $c$ in terms of $b$.**
$$\frac{b}{c} = \frac{7}{3} \Rightarrow c = \frac{3}{7}b$$
7. **Step 6: Substitute $b = \frac{3}{8}a$ into $c = \frac{3}{7}b$.**
$$c = \frac{3}{7} \times \frac{3}{8}a = \frac{9}{56}a$$
8. **Step 7: Write the ratio $a : b : c$ using a common denominator.**
$$a : b : c = a : \frac{3}{8}a : \frac{9}{56}a$$
9. **Step 8: Multiply all terms by 56 to clear denominators.**
$$56a : 56 \times \frac{3}{8}a : 56 \times \frac{9}{56}a = 56a : 21a : 9a$$
10. **Step 9: Simplify by dividing all terms by $a$.**
$$56 : 21 : 9$$
**Final answer:**
$$a : b : c = 56 : 21 : 9$$
Ratio Abc Ae4F60
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