1. **State the problem:** We have a ratio table with two columns. The first column is 6, 36, 54, 60, 84 and the second column is 5, 30, ?, ?, 70. We need to find the missing values in the second column. 2. **Understand the ratio:** The ratio between the first and second columns should be constant. Let's find the ratio using the first row: $$\frac{6}{5}$$. 3. **Check the ratio for the second row:** $$\frac{36}{30} = \frac{6}{5}$$, which confirms the ratio is consistent. 4. **Use the ratio to find missing values:** For the third row, let the missing value be $x$. We have $$\frac{54}{x} = \frac{6}{5}$$. 5. **Solve for $x$:** $$54 \times 5 = 6 \times x$$ $$270 = 6x$$ $$x = \frac{270}{6}$$ $$x = 45$$ 6. **For the fourth row, let the missing value be $y$:** $$\frac{60}{y} = \frac{6}{5}$$ 7. **Solve for $y$:** $$60 \times 5 = 6 \times y$$ $$300 = 6y$$ $$y = \frac{300}{6}$$ $$y = 50$$ 8. **Verify the last row:** $$\frac{84}{70} = \frac{6}{5}$$, which is true. **Final completed table:** | 6 | 5 | | 36 | 30 | | 54 | 45 | | 60 | 50 | | 84 | 70 | The missing values are 45 and 50.