1. **State the problem:** We need to find the value of $T = \frac{m}{f}$ given the ranges for $m$ and $f$. 2. **Given data:** - $m$ is between 119.5 and 120.5 (correct to 3 significant figures). - $f$ is between 25.55 and 26.65 (correct to 1 decimal place). 3. **Calculate the minimum value of $T$:** Since $T = \frac{m}{f}$, the minimum $T$ occurs when $m$ is minimum and $f$ is maximum. $$T_{min} = \frac{119.5}{26.65} \approx 4.4847$$ 4. **Calculate the maximum value of $T$:** The maximum $T$ occurs when $m$ is maximum and $f$ is minimum. $$T_{max} = \frac{120.5}{25.55} \approx 4.7162$$ 5. **Interpretation:** The value of $T$ lies between approximately 4.48 and 4.72 given the uncertainties in $m$ and $f$. 6. **Final answer:** $$4.48 \leq T \leq 4.72$$ This range accounts for the possible variation in $m$ and $f$ based on their given precision.