1. Problem: Find vertical and horizontal asymptotes, intercepts, domain, and range of the rational function with vertical asymptotes at $x=-2$ and $x=2$, and horizontal asymptotes at $y=-1$ and $y=1$. 2. Vertical asymptotes occur where the denominator is zero and the function is undefined. Given: vertical asymptotes at $x=-2$ and $x=2$. 3. Horizontal asymptotes describe end behavior. Given: horizontal asymptotes at $y=-1$ and $y=1$. 4. Intercepts: - $x$-intercepts are points where $f(x)=0$. - $y$-intercepts are points where $x=0$. 5. From the graph description and options: - $x$-intercepts: $3$, $-4$, $-2$, None. Since $x=-2$ is a vertical asymptote, it cannot be an $x$-intercept. The graph likely crosses at $3$ and $-4$. So $x$-intercepts: $3$ and $-4$. - $y$-intercepts: options $1$, $-2$, $0$, None. The graph likely crosses $y=0$ at $x=0$, so $y$-intercept is $0$. 6. Domain: All real numbers except where vertical asymptotes occur. Domain: $(-\infty,-2) \cup (-2,2) \cup (2,\infty)$. 7. Range: Since horizontal asymptotes are $y=-1$ and $y=1$, and the graph approaches but does not cross these lines, range excludes these values. Range: $(-\infty,-1) \cup (-1,1) \cup (1,\infty)$. Final answers: Vertical asymptotes: $x=-2$ and $x=2$ Horizontal asymptotes: $y=-1$ and $y=1$ $x$-intercepts: $3$ and $-4$ $y$-intercept: $0$ Domain: $(-\infty,-2) \cup (-2,2) \cup (2,\infty)$ Range: $(-\infty,-1) \cup (-1,1) \cup (1,\infty)$