1. **State the problem:** Simplify the expression $$\frac{x^2 - 25}{x^2 + 5x} \div \frac{xy + 6x - 5y - 30}{5x - 15}$$. 2. **Rewrite division as multiplication by reciprocal:** $$\frac{x^2 - 25}{x^2 + 5x} \times \frac{5x - 15}{xy + 6x - 5y - 30}$$ 3. **Factor all polynomials:** - $x^2 - 25 = (x - 5)(x + 5)$ (difference of squares) - $x^2 + 5x = x(x + 5)$ - $5x - 15 = 5(x - 3)$ - Factor $xy + 6x - 5y - 30$ by grouping: $$xy + 6x - 5y - 30 = x(y + 6) - 5(y + 6) = (x - 5)(y + 6)$$ 4. **Substitute factored forms:** $$\frac{(x - 5)(x + 5)}{x(x + 5)} \times \frac{5(x - 3)}{(x - 5)(y + 6)}$$ 5. **Cancel common factors:** - Cancel $(x + 5)$ in numerator and denominator - Cancel $(x - 5)$ in numerator and denominator Intermediate step showing cancellation: $$\frac{\cancel{(x - 5)}\cancel{(x + 5)}}{x\cancel{(x + 5)}} \times \frac{5(x - 3)}{\cancel{(x - 5)}(y + 6)} = \frac{1}{x} \times \frac{5(x - 3)}{y + 6}$$ 6. **Multiply remaining factors:** $$\frac{1}{x} \times \frac{5(x - 3)}{y + 6} = \frac{5(x - 3)}{x(y + 6)}$$ **Final answer:** $$\boxed{\frac{5(x - 3)}{x(y + 6)}}$$