1. **Stating the problem:** Simplify the expression $$\frac{-22-4xh}{14-2xh} \div \frac{22-14xh}{x^2-8x-28} \div \frac{x^2-6x}{x^2-6x}.$$ 2. **Rewrite the division as multiplication by the reciprocal:** $$\frac{-22-4xh}{14-2xh} \times \frac{x^2-8x-28}{22-14xh} \times \frac{x^2-6x}{x^2-6x}.$$ 3. **Factor where possible:** - Factor numerator and denominator terms involving $x$ and $h$: $$-22-4xh = -2(11+2xh), \quad 14-2xh = 2(7-xh), \quad 22-14xh = 2(11-7xh).$$ - Factor quadratic $x^2-8x-28$: $$x^2-8x-28 = (x-14)(x+2).$$ - Factor $x^2-6x$: $$x^2-6x = x(x-6).$$ 4. **Rewrite expression with factors:** $$\frac{-2(11+2xh)}{2(7-xh)} \times \frac{(x-14)(x+2)}{2(11-7xh)} \times \frac{x(x-6)}{x(x-6)}.$$ 5. **Cancel common factors:** - Cancel 2 in numerator and denominator of first fraction: $$\frac{\cancel{-2}(11+2xh)}{\cancel{2}(7-xh)} = \frac{-(11+2xh)}{7-xh}.$$ - Cancel $x(x-6)$ in last fraction: $$\frac{\cancel{x}\cancel{(x-6)}}{\cancel{x}\cancel{(x-6)}} = 1.$$ 6. **Combine remaining terms:** $$\frac{-(11+2xh)}{7-xh} \times \frac{(x-14)(x+2)}{2(11-7xh)} \times 1 = \frac{-(11+2xh)(x-14)(x+2)}{2(7-xh)(11-7xh)}.$$ 7. **Final simplified expression:** $$\boxed{\frac{-(11+2xh)(x-14)(x+2)}{2(7-xh)(11-7xh)}}.$$