1. **State the problem:**
We analyze the function's domain, range, intercepts, and asymptotes based on the description of a hyperbola-like rational function with two branches.
2. **Domain:**
The vertical asymptote is at $x=1$, so the function is undefined there.
Thus, the domain is all real numbers except $x=1$.
In interval notation: $$(-\infty, 1) \cup (1, \infty)$$
3. **Range:**
The horizontal asymptote is $y=2$, and the branches approach this line but do not cross it.
The function has values both above and below $y=2$.
Since one branch is in the first quadrant (positive $y$) and the other in the third/fourth quadrants (negative $y$), the range is all real numbers except $y=2$.
In interval notation: $$(-\infty, 2) \cup (2, \infty)$$
4. **x-intercepts:**
To find $x$-intercepts, set $y=0$ and solve for $x$.
Since the graph crosses the $x$-axis (implied by branches in third/fourth quadrants), there are $x$-intercepts.
Exact values depend on the function formula, but since not given, we state:
$x=$ values where $y=0$ (exists).
5. **y-intercepts:**
Set $x=0$ and find $y$.
Since the function is defined at $x=0$ (domain excludes only $x=1$), there is a $y$-intercept.
Exact value depends on the function formula.
6. **Horizontal asymptotes:**
Given as $y=2$.
7. **Vertical asymptotes:**
Given as $x=1$.
8. **Oblique asymptotes:**
None, as the function has a horizontal asymptote.
**Summary:**
- Domain: $$(-\infty, 1) \cup (1, \infty)$$
- Range: $$(-\infty, 2) \cup (2, \infty)$$
- x-intercepts: exist, exact values depend on function
- y-intercept: exists, exact value depends on function
- Horizontal asymptote: $$y=2$$
- Vertical asymptote: $$x=1$$
- Oblique asymptotes: none
Since no explicit function is given, exact intercept values cannot be computed.
Rational Function Analysis 69C660
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