1. The problem is to understand why we only find factors of 8 when factoring the polynomial $x^3 + x^3 - 10x + 8$ using the Rational Root Theorem. 2. The polynomial can be simplified first: $x^3 + x^3 = 2x^3$, so the polynomial is actually $2x^3 - 10x + 8$. 3. The Rational Root Theorem states that any rational root, expressed as $\frac{p}{q}$, must have $p$ as a factor of the constant term and $q$ as a factor of the leading coefficient. 4. Here, the constant term is 8, and the leading coefficient is 2. 5. Therefore, possible values for $p$ are factors of 8: $\pm1, \pm2, \pm4, \pm8$. 6. Possible values for $q$ are factors of 2: $\pm1, \pm2$. 7. Hence, possible rational roots are $\pm1, \pm2, \pm4, \pm8, \pm\frac{1}{2}, \pm\frac{2}{2} (\text{which simplifies to } \pm1), \pm\frac{4}{2} (\pm2), \pm\frac{8}{2} (\pm4)$. 8. So, the reason we consider factors of 8 is because 8 is the constant term, not because the leading coefficient is 1. 9. Since the leading coefficient is 2, we must also consider factors of 2 in the denominator. 10. Therefore, the answer to your question is **No**, the reason we find factors of 8 is because it is the constant term, not because the leading coefficient is 1. Final answer: No, the factors of 8 come from the constant term, not the leading coefficient.