1. **State the problem:** We are given a polynomial and have found one rational zero using synthetic division. Now, we need to find the quadratic factor from the division and solve it to find the remaining two zeros, which are irrational. 2. **Quadratic factor:** After synthetic division by the rational zero, the polynomial reduces to a quadratic factor. Suppose this quadratic factor is $$ax^2 + bx + c = 0$$. 3. **Solve the quadratic equation:** Use the quadratic formula: $$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$$ 4. **Calculate the discriminant:** $$\Delta = b^2 - 4ac$$. Since the remaining zeros are irrational, $$\Delta$$ is positive but not a perfect square. 5. **Find the zeros:** Substitute $$a$$, $$b$$, and $$c$$ into the quadratic formula to find the two irrational zeros. 6. **Express the zeros:** Write the zeros either in exact form with square roots or as decimals rounded to at least three decimal places. **Final answer:** The two remaining zeros are $$\frac{-b + \sqrt{b^2 - 4ac}}{2a}$$ and $$\frac{-b - \sqrt{b^2 - 4ac}}{2a}$$ (or their decimal approximations).