1. **State the problem:** Simplify the expression $$\frac{2}{\sqrt[3]{3} - \sqrt[4]{5}}$$.
2. **Formula and rules:** To simplify expressions with radicals in the denominator, we rationalize the denominator by multiplying numerator and denominator by the conjugate or an expression that removes the radicals.
3. **Identify the conjugate:** The denominator is $$\sqrt[3]{3} - \sqrt[4]{5}$$. Its conjugate is $$\sqrt[3]{3} + \sqrt[4]{5}$$.
4. **Multiply numerator and denominator by the conjugate:**
$$\frac{2}{\sqrt[3]{3} - \sqrt[4]{5}} \times \frac{\sqrt[3]{3} + \sqrt[4]{5}}{\sqrt[3]{3} + \sqrt[4]{5}} = \frac{2(\sqrt[3]{3} + \sqrt[4]{5})}{(\sqrt[3]{3})^2 - (\sqrt[4]{5})^2}$$
5. **Simplify the denominator:**
$$(\sqrt[3]{3})^2 = 3^{\frac{2}{3}}$$
$$(\sqrt[4]{5})^2 = 5^{\frac{1}{2}}$$
So denominator becomes:
$$3^{\frac{2}{3}} - 5^{\frac{1}{2}}$$
6. **Final simplified expression:**
$$\frac{2(\sqrt[3]{3} + \sqrt[4]{5})}{3^{\frac{2}{3}} - 5^{\frac{1}{2}}}$$
This is the simplified form with a rationalized denominator.
**Answer:** $$\boxed{\frac{2(\sqrt[3]{3} + \sqrt[4]{5})}{3^{\frac{2}{3}} - 5^{\frac{1}{2}}}}$$
Rationalize Denominator Dc2F73
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