1. **State the problem:** Write $\frac{4 - \sqrt{3}}{\sqrt{3}}$ in the form $\frac{a\sqrt{3} + b}{c}$ where $a$, $b$, and $c$ are integers. 2. **Start with the given expression:** $$\frac{4 - \sqrt{3}}{\sqrt{3}}$$ 3. **Separate the fraction into two parts:** $$\frac{4}{\sqrt{3}} - \frac{\sqrt{3}}{\sqrt{3}}$$ 4. **Simplify the second term:** $$\frac{\sqrt{3}}{\sqrt{3}} = 1$$ So the expression becomes: $$\frac{4}{\sqrt{3}} - 1$$ 5. **Rationalize the denominator of the first term:** Multiply numerator and denominator by $\sqrt{3}$: $$\frac{4}{\sqrt{3}} \times \frac{\sqrt{3}}{\sqrt{3}} = \frac{4\sqrt{3}}{3}$$ 6. **Rewrite the expression:** $$\frac{4\sqrt{3}}{3} - 1 = \frac{4\sqrt{3}}{3} - \frac{3}{3} = \frac{4\sqrt{3} - 3}{3}$$ 7. **Final form:** $$\frac{4\sqrt{3} - 3}{3}$$ Here, $a = 4$, $b = -3$, and $c = 3$ are integers. **Answer:** $$\frac{4\sqrt{3} - 3}{3}$$