1. The problem asks whether the statement "The graph of a reciprocal of a quadratic function decreases on its domain when the graph of the quadratic function increases on the same domain" is true or false.
2. Let the quadratic function be $f(x)$ and its reciprocal be $g(x) = \frac{1}{f(x)}$.
3. If $f(x)$ is increasing on some interval, then for $x_1 < x_2$ in that interval, $f(x_1) < f(x_2)$.
4. Since $g(x) = \frac{1}{f(x)}$, if $f(x)$ is positive and increasing, then $g(x_1) = \frac{1}{f(x_1)} > \frac{1}{f(x_2)} = g(x_2)$, so $g(x)$ is decreasing.
5. Similarly, if $f(x)$ is negative and increasing (values becoming less negative), $g(x)$ will also decrease in magnitude but the behavior depends on the sign; however, generally, the reciprocal function's monotonicity is opposite to that of the original function where the function does not cross zero.
6. Therefore, the statement is generally true on intervals where $f(x)$ does not change sign.
Final answer: True
Reciprocal Quadratic A9E1C9
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