1. **State the problem:** We need to find the area of the entire large rectangle, which is divided into three smaller rectangles horizontally.
2. **Identify dimensions:** The height of the entire rectangle is given as $5m^4$.
3. **Width of the entire rectangle:** The width is the sum of the widths of the three smaller rectangles. The right rectangle's width is given as $m^2 - 2m - 1$ (rewriting $m^2 + -2m + -1$ in standard form). The widths of the other two rectangles are not explicitly given, so we assume the total width is $m^2 - 2m - 1$.
4. **Formula for area of a rectangle:**
$$\text{Area} = \text{height} \times \text{width}$$
5. **Calculate the area:**
$$\text{Area} = 5m^4 \times (m^2 - 2m - 1)$$
6. **Distribute multiplication:**
$$= 5m^4 \times m^2 - 5m^4 \times 2m - 5m^4 \times 1$$
$$= 5m^{6} - 10m^{5} - 5m^{4}$$
7. **Final answer:** The area of the entire rectangle expressed as a polynomial in standard form is:
$$\boxed{5m^{6} - 10m^{5} - 5m^{4}}$$
Rectangle Area 145Bc9
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